用参数换元法解（xy/2=z+x/3=y+x/4；（x+y+z=27

Question

用参数换元法解（xy/2=z+x/3=y+x/4； （x+y+z=27

Answer 1

先从x+y+z=27入手,例如x=27-y-z,然后利用它去代入xy/2=z+x/3=y+x/4这个式子,去解出y和z,在代回x+y+z=27,解出x