若x,y是实数,且y＜√x-1+√1-x+1/2,求∣1-y∣/y-1摆脱要清楚点,

Question

若x,y是实数,且y＜√x-1+√1-x+1/2,求∣1-y∣/y-1
摆脱要清楚点,

Answer 1

y定义域为x-1≥0且1-x≥0
定义域只有一个值即x=1
将x=1代入方程,得：y<0+0+1/2=1/2
∴|1-y|/(y-1)=(1-y)/(y-1)=-1