[-1/(2)ab²c]²·[-1/(3)abc]³·12a³b{[4x-(1)/(2)y]²+4y[x-(y)/(16)]}÷8x²

Question

[-1/(2)ab²c]²·[-1/(3)abc]³·12a³b
{[4x-(1)/(2)y]²+4y[x-(y)/(16)]}÷8x²

Answer 1

[-1/(2)ab²c]²·[-1/(3)abc]³·12a³b
=（-1/2)²·(ab²c)²·(-1/3)³(abc)³·12a³b
=1/4·(-1/27）·12·a²b^4c²·a³b³c³·a³b
=(-1/9)·a^8·b^8·c^5 (注:a^8为a的八次方)

{[4x-(1)/(2)y]²+4y[x-(y)/(16)]}÷8x²
=[(4x)²-2·4x·(1/2y)+(1/2y)²+(4y·x-4y·(y/16)]×(8/x²)
=[16x²-4xy+(1/4y²)+4xy-(1/4y²)]·(8/x²)
=16x²·(8/x²)
=2