求定积分:∫（上标是+∞,下标是-∞）dx/[(1+x^2)^(3/2)]=

Question

求定积分:∫（上标是+∞ ,下标是-∞）dx/[(1+x^2)^(3/2)]=

Answer 1

换元,令x=tant.代入积分式,有原式=∫（上限为π/2,下限为-π/2）costdt=2