帮忙解个二元一次方程组（x+y）/2-(x-y)/3=5/6{(x+y)/6+(x-y)/3=1/2

Question

帮忙解个二元一次方程组
（x+y）/2-(x-y)/3=5/6
{
(x+y)/6+(x-y)/3=1/2

Answer 1

两个方程相加
(x+y)/2+(x+y)/6=5/6+1/2
(2/3)(x+y)=4/3
x+y=2 (1)
代入(x+y)/2-(x-y)/3=5/6
1-(x-y)/3=5/6
(x-y)/3=1/6
x-y=1/2 (2)
(1)+(2)
2x=5/2
x=5/4
y=x-1/2=3/4