根号（2/3）-4根号216+42根号（1/6)

Question

根号（2/3）-4根号216+42根号（1/6)

Answer 1

√(2/3)-4√216+42√(1/6)
=[√(2/3)][(√3)/(√3)]-4√(6^3)216+42√(1/6)[(√6)/(√6)]
=(1/3)√6-4×6√6+(42√6)/6
=(1/3)√6-24√6+7√6
=[(1/3)-24+7]√6
=-(50√6)/3