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1.将下列三角函数化为锐角三角函数(1)tan3/5π=(2)tan100°21′=(3)tan31/36π=(4)tan324°32′=2.用诱导公式求下列三角函数值(要过程)(1)cos65/6π(2)sin(-31/4π)(3)cos(-1182°13′)
题目详情
1.将下列三角函数化为锐角三角函数
(1)tan3/5π= (2)tan100°21′=
(3)tan31/36π= (4)tan324°32′=
2.用诱导公式求下列三角函数值(要过程)
(1)cos65/6π (2)sin(-31/4π)(3)cos(-1182°13′)
(4)sin670°39′ (5)tan(-26π/3) (6)tan580°21′
(1)tan3/5π= (2)tan100°21′=
(3)tan31/36π= (4)tan324°32′=
2.用诱导公式求下列三角函数值(要过程)
(1)cos65/6π (2)sin(-31/4π)(3)cos(-1182°13′)
(4)sin670°39′ (5)tan(-26π/3) (6)tan580°21′
▼优质解答
答案和解析
tan3π/5= tan(π-2π/5)=-tan2π/5,
tan100°21′=tan(180°-79°39′)=-tan79°39′
tan31π/36= tan(π-5π/36)=-tan5π/36
tan324°32′=tan(360°-35°28′)=-tan35°28′
cos65π/6=cos(60+5)π/6=cos5π/6=cos(π-π/6)=-cosπ/6=负的2分之根号3
sin(-31π/4)=sin(-32+1)π/4=sin(π/4)=2分之根号2
cos(-1182°13′)=cos(-1080°-102°13′)=cos(-102°13′)=cos102°13′=cos(180°-77°47′)=-cos77°47′
sin670°39′=sin720°-49°21′=-sin49°21′
tan(-26π/3)=tan(-24-2)π/3=tan-2π/3=-tan2π/3=-tan(π-π/3)=tanπ/3=根号3
tan580°21′=tan(720°-139°39′)=-tan(180°-40°21′)=tan40°21′
tan100°21′=tan(180°-79°39′)=-tan79°39′
tan31π/36= tan(π-5π/36)=-tan5π/36
tan324°32′=tan(360°-35°28′)=-tan35°28′
cos65π/6=cos(60+5)π/6=cos5π/6=cos(π-π/6)=-cosπ/6=负的2分之根号3
sin(-31π/4)=sin(-32+1)π/4=sin(π/4)=2分之根号2
cos(-1182°13′)=cos(-1080°-102°13′)=cos(-102°13′)=cos102°13′=cos(180°-77°47′)=-cos77°47′
sin670°39′=sin720°-49°21′=-sin49°21′
tan(-26π/3)=tan(-24-2)π/3=tan-2π/3=-tan2π/3=-tan(π-π/3)=tanπ/3=根号3
tan580°21′=tan(720°-139°39′)=-tan(180°-40°21′)=tan40°21′
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