亲爱的网友：f（x）=（根号下x^2-3x-4）/x1a3b3(2x-14)/(x^2-1)

Question

亲爱的网友：f（x）=（根号下x^2-3x-4）/x 1a3 b3
(2x-14) / (x^2-1) <= -1A= b=

Answer 1

∴a b≥2√ab 1/(a b)≤1/2√ab.相对A×B＝{a 2,2a,a 3,2a 1相对f(x)=2acos^2x bsinxcosx1.2（x 3)2=x(x 3) 2.x22根号5x 2=0