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(1)3318+312÷24×205(2)47.1×9.4-47.1÷2-+47.1(3)[(1-0.5)×20]÷[(1+0.25)÷4](4)12−13+14(5)100-99+98-97+96-…+4-3+2-1(6)15×6+16×7+17×8+−−−−−−+149×50.
题目详情
(1)3318+312÷24×205
(2)47.1×9.4-47.1÷2-+47.1
(3)[(1-0.5)×20]÷[(1+0.25)÷4]
(4)
−
+
(5)100-99+98-97+96-…+4-3+2-1
(6)
+
+
+ −−−−−−+
.
(2)47.1×9.4-47.1÷2-+47.1
(3)[(1-0.5)×20]÷[(1+0.25)÷4]
(4)
1 |
2 |
1 |
3 |
1 |
4 |
(5)100-99+98-97+96-…+4-3+2-1
(6)
1 |
5×6 |
1 |
6×7 |
1 |
7×8 |
1 |
49×50 |
▼优质解答
答案和解析
(1)3318+312÷24×205,
=3318+13×205,
=3318+2665,
=5983;
(2)47.1×9.4-47.1÷2-47.1,
=47.1×(9.4-0.5-1),
=47.1×7.9,
=372.09;
(3)[(1-0.5)×20]÷[(1+0.25)÷4],
=10÷0.3125,
=32;
(4)
−
+
,
=(
+
)−
,
=
−
,
=
;
(5)100-99+98-97+96-…+4-3+2-1,
=(100-99)+(98-97)+(96-95)+…+(4-3)+(2-1),
=1×50,
=50;
(6)
+
+
+… +
,
=(
−
)+(
−
) +(
−
)+…+(
−
),
=
−
,
=
.
=3318+13×205,
=3318+2665,
=5983;
(2)47.1×9.4-47.1÷2-47.1,
=47.1×(9.4-0.5-1),
=47.1×7.9,
=372.09;
(3)[(1-0.5)×20]÷[(1+0.25)÷4],
=10÷0.3125,
=32;
(4)
1 |
2 |
1 |
3 |
1 |
4 |
=(
1 |
2 |
1 |
4 |
1 |
3 |
=
3 |
4 |
1 |
3 |
=
5 |
12 |
(5)100-99+98-97+96-…+4-3+2-1,
=(100-99)+(98-97)+(96-95)+…+(4-3)+(2-1),
=1×50,
=50;
(6)
1 |
5×6 |
1 |
6×7 |
1 |
7×8 |
1 |
49×50 |
=(
1 |
5 |
1 |
6 |
1 |
6 |
1 |
7 |
1 |
7 |
1 |
8 |
1 |
49 |
1 |
50 |
=
1 |
5 |
1 |
50 |
=
9 |
50 |
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