lg5×lg8000+（lg2根3）方+lg0.06-lg6那个，中间是（lg2倍的根3）方

Question

lg5×lg8000+（lg2根3）方+lg0.06-lg6
那个，中间是（lg2倍的根3）方

Answer 1

要运用对数法则
lg5*lg8000+（lg2^根号3）^2+lg0.06-lg6
=lg5*(lg8+lg1000)+(√3*lg2)^2+lg(6/100)-lg6
=lg5*(3lg2+3)+3*(lg2)^2+lg[(6/100)/6]
=3lg2*lg5+3lg5+3(lg2)^2+lg(1/100)
=3lg2(lg2+lg5)+3lg5+lg10^(-2)
=3lg2*lg10+3*lg5-2
=3lg2+3lg5-2
=3(lg2+lg5)-2
=3*1-2
=1