{x+y=1,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0

Question

{x+y=1 ,xy=-6
{x(2x-3)=0,y=x²-1
{(3x+4y-3)(3x+4y+3)=0,3x+2y=5
{(x-y+2)(x+y)=0,x²+y²=8
{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0

Answer 1

x = -2,y = 3     或
x = 3,y = -2
x = 0,y = -1     或
x = 3/2,y = 5/4
x = 13/3,y = -4     或
x = 7/3,y = -1
x = 2,y = -2     或
x = -2,y = 2     或
x = -√3-1,y = 1-√3     或
x = √3-1,y = √3+1
x = 0,y = 0      或
x = 1/2,y = 1/2     或
x = 1/2,y = -1/2     或
x = 1,y = 0