已知x/2=y/3=z/4,且x+y-z=1/12,求x,y,z

Question

已知x/2=y/3=z/4,且x+y-z=1/12,求x,y,z

Answer 1

x/2=y/3=z/4=k
x=2k,y=3k,z=4k
x+y-z=1/12
即 2k+3k-4k=1/12
k=1/12
x=1/6
y=1/4
z=1/3