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计算和解分式方程:(1)xx2-1•x2+xx2;(2)(-1)2016-|-2|+(3-π)0×38+(14)-1;(3)3x=5x+2;(4)3x+2+1x=4x2+2x.

题目详情
计算和解分式方程:
(1)
x
x2-1
x2+x
x2

(2)(-1)2016-|-2|+(
3
-π)0×
38
+(
1
4
-1
(3)
3
x
=
5
x+2

(4)
3
x+2
+
1
x
=
4
x2+2x
计算和解分式方程:
(1)
x
x2-1
x2+x
x2

(2)(-1)2016-|-2|+(
3
-π)0×
38
+(
1
4
-1
(3)
3
x
=
5
x+2

(4)
3
x+2
+
1
x
=
4
x2+2x

x
x2-1
x2+x
x2

(2)(-1)2016-|-2|+(
3
-π)0×
38
+(
1
4
-1
(3)
3
x
=
5
x+2

(4)
3
x+2
+
1
x
=
4
x2+2x
x
x2-1
xx2-1xxx2-1x2-1x2-1x2-12-1
x2+x
x2

(2)(-1)2016-|-2|+(
3
-π)0×
38
+(
1
4
-1
(3)
3
x
=
5
x+2

(4)
3
x+2
+
1
x
=
4
x2+2x
x2+x
x2
x2+xx2x2+xx2+xx2+xx2+x2+xx2x2x2x22
2016
3
-π)0×
38
+(
1
4
-1
(3)
3
x
=
5
x+2

(4)
3
x+2
+
1
x
=
4
x2+2x
3
3
3
30
38
+(
1
4
-1
(3)
3
x
=
5
x+2

(4)
3
x+2
+
1
x
=
4
x2+2x
38
38
3838
1
4
-1
(3)
3
x
=
5
x+2

(4)
3
x+2
+
1
x
=
4
x2+2x
1
4
141144-1
3
x
=
5
x+2

(4)
3
x+2
+
1
x
=
4
x2+2x
3
x
3x33xx
5
x+2

(4)
3
x+2
+
1
x
=
4
x2+2x
5
x+2
5x+255x+2x+2
3
x+2
+
1
x
=
4
x2+2x
3
x+2
3x+233x+2x+2
1
x
=
4
x2+2x
1
x
1x11xx
4
x2+2x
4
x2+2x
4x2+2x44x2+2xx2+2xx2+2xx2+2x2+2x
▼优质解答
答案和解析
(1)原式=
x
(x+1)(x-1)
x(x+1)
x2
=
1
x-1

(2)原式=1-2+2+4=5;
(3)去分母得:3x+6=5x,
移项合并得:2x=6,
解得:x=3,
经检验x=3是分式方程的解;
(4)去分母得:3x+x+2=4,
解得:x=
1
2

经检验x=
1
2
是分式方程的解.
x
(x+1)(x-1)
x(x+1)(x-1)xxx(x+1)(x-1)(x+1)(x-1)(x+1)(x-1)•
x(x+1)
x2
=
1
x-1

(2)原式=1-2+2+4=5;
(3)去分母得:3x+6=5x,
移项合并得:2x=6,
解得:x=3,
经检验x=3是分式方程的解;
(4)去分母得:3x+x+2=4,
解得:x=
1
2

经检验x=
1
2
是分式方程的解.
x(x+1)
x2
x(x+1)x2x(x+1)x(x+1)x(x+1)x2x2x22=
1
x-1

(2)原式=1-2+2+4=5;
(3)去分母得:3x+6=5x,
移项合并得:2x=6,
解得:x=3,
经检验x=3是分式方程的解;
(4)去分母得:3x+x+2=4,
解得:x=
1
2

经检验x=
1
2
是分式方程的解.
1
x-1
1x-1111x-1x-1x-1;
(2)原式=1-2+2+4=5;
(3)去分母得:3x+6=5x,
移项合并得:2x=6,
解得:x=3,
经检验x=3是分式方程的解;
(4)去分母得:3x+x+2=4,
解得:x=
1
2

经检验x=
1
2
是分式方程的解.
1
2
12111222,
经检验x=
1
2
是分式方程的解.
1
2
12111222是分式方程的解.