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高数y‘’=1/√y,即y的两次导=根号y分之一
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高数 y‘’=1/√y,即y的两次导=根号y分之一
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答案和解析
设 y ' = P(y),y '' = P * dP/dy
P * dP/dy = 1/√y => (2P) * dP = 2dy/√y
=> P^2 = 4√y + C1
=> P = ±√( 4√y + C1)
即 ±dy/√( 4√y + C1) = dx
=> x = ± ∫ dy/√( 4√y + C1) + C2
P * dP/dy = 1/√y => (2P) * dP = 2dy/√y
=> P^2 = 4√y + C1
=> P = ±√( 4√y + C1)
即 ±dy/√( 4√y + C1) = dx
=> x = ± ∫ dy/√( 4√y + C1) + C2
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