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m(t)=[u（t）-u(t-t0/3)]+2[u(t-t0/3)-u(t-2t0/3)]杂求它的傅立叶变换啊?
题目详情
m(t)=[u（t）-u(t-t0/3)]+2[u(t-t0/3)-u(t-2t0/3)]杂求它的傅立叶变换啊?
▼优质解答
答案和解析
F[u(t)] = πδ(ω) + 1/jω
F[u(t-a)] = e^(-jωa) * [πδ(ω) + 1/jω]
F[m(t)] = [πδ(ω) + 1/jω][1 + e^(-jωt0/3) - 2e^(-2jωt0/3)]
F[u(t-a)] = e^(-jωa) * [πδ(ω) + 1/jω]
F[m(t)] = [πδ(ω) + 1/jω][1 + e^(-jωt0/3) - 2e^(-2jωt0/3)]
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