[(10.75-4又十二分之11）X2又十一分之七]÷[（1.125+十二分之一）÷（2.25÷10又十一分之十）]

Question

[(10.75-4又十二分之11）X2又十一分之七]÷[（1.125+十二分之一）÷（2.25÷10又十一分之十）]

Answer 1

[(10.75-4又十二分之11）X2又十一分之七]÷[（1.125+十二分之一）÷（2.25÷10又十一分之十）]
=[(10+3/4-4-11/12)X(2+7/11)]÷{(1+1/8+1/12)÷[(2+1/4)÷(10+10/11)]}
=[(6+9/12-11/12)X(29/11)]÷{(1+3/24+2/24)÷[(9/4)÷(120/11)]}
=[(6-1/6)X(29/11)]÷{(1+5/24)÷[(9/4)÷(120/11)]}
=[(35/6)X(29/11)]÷{(29/24)÷[(9/4)÷(120/11)]}
=[(35/6)X(29/11)]÷{(29/24)÷[4/9X11/120]}
=[(35/6)X(29/11)]÷{(29/24)÷(11/270)}
=[(35/6)X(29/11)]÷{(29/24)X(270/11)}
=[(35X29)/(6X11)]÷{(29X270)/(24X11)}
=[(35X29)/(6X11)]X(24X11)/(29X270)
=(35X4)/270
=140/270
=14/27