用换元法求不定积分,1/(1+x)(x+2),答案为ln|(x+1)/(x+2)|+1/(x+2)+c,

Question

用换元法求不定积分,1/(1+x)(x+2),答案为ln|(x+1)/(x+2)|+1/(x+2)+c,

Answer 1

1/(1+x)(x+2)=1/(x+1)-1/(x+2)
剩下的就很简单的了呵 你的答案是不正确的,
应该是：ln|(x+1)/（x+2）|+c