求积分(0~1)x/根号下(1-x^2)dx敛散性,

Question

求积分(0~1)x/根号下(1-x^2)dx敛散性,

Answer 1

∫ xdx/√(1-x^2)
= (-1/2)∫ d(1-x^2)/√(1-x^2)
= [-√(1-x^2)] = 1, 则积分收敛.