将0.1mol/L NaOH与0.3mol/LNaOH等体积混合,求PH=?

Question

将0.1mol/L NaOH与0.3mol/LNaOH等体积混合,求PH=?

Answer 1

[OH-]=(0.1mol/L +0.3mol/L)/2=0.2mol/L
[H+]=Kw /[OH-]=1.0×10^(-14) /0.2=5×10^(-14)
pH=-lg[H+]=lg5×10^(-14) =13.3