tanα=1/2,tanβ=1/3,α、β均为锐角,则α+β=

Question

tanα=1/2,tanβ=1/3,α、β均为锐角,则α+β=

Answer 1

tan(α+β)=(tanα+tanβ)/(1-tanαtanβ)
=(1/2+1/3)/(1-1/6)
=1
又因为α、β均为锐角,所以 0