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基础训练数学已知（2x-3)/(x+2)(x-3)=A/(x+2)-B/(x-3),求整式A,B
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(2x-3)/(x+2)(x-3）=A/(x+2)-B/(x-3)
(2x-3)/(x+2)(x-3）=[A(x-3)-B(x+2)]/(x+2)(x-3)
(2x-3)/(x+2)(x-3）=[(A-B)x-2B-3A]/(x+2)(x-3)
(2x-3)=[(A-B)x-2B-3A]
A-B=2
3A+2B=3
A=7/5
B=-3/5
(2x-3)/(x+2)(x-3）=[A(x-3)-B(x+2)]/(x+2)(x-3)
(2x-3)/(x+2)(x-3）=[(A-B)x-2B-3A]/(x+2)(x-3)
(2x-3)=[(A-B)x-2B-3A]
A-B=2
3A+2B=3
A=7/5
B=-3/5
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