计算6sin(-90度)+3sin0度-8sin270度+12cos180度6sin(-90度)+3sin0度-8sin270度+12cos180度10cos270度+4sin0度+9tan0度+15cos360度2cosπ/2-tanπ/4+3/4tan^2π/6/-sinπ/6+cos^2π/6+sin3π/2sin^2π/3+cos^43π/2-tan^2π/3写上详细过程，

Question

计算6sin(-90度)+3sin0度-8sin270度+12cos180度
6sin(-90度)+3sin0度-8sin270度+12cos180度
10cos270度+4sin0度+9tan0度+15cos360度
2cosπ/2-tanπ/4+3/4tan^2 π/6/-sinπ/6+cos^2 π/6+sin3π/2
sin^2 π/3+cos^4 3π/2-tan^2 π/3
写上详细过程，谢谢，自己做的感觉怪怪滴……

Answer 1

6sin(-90度)+3sin0度-8sin270度+12cos180度
=6*(-1)+3*0-8*(-1)+12*(-1)=-10
10cos270度+4sin0度+9tan0度+15cos360度
=10*0+4*0+9*0+15*1
=15
2cosπ/2-tanπ/4+3/4tan^2 π/6/-sinπ/6+cos^2 π/6+sin3π/2
cosπ/2=0
tanπ/4=1
(tanπ/6)^2=(√3/3)^2=1/3
sinπ/6=1/2
(cosπ/6)^2=(√3/2)^2=3/4
sin3π/2=-1
所以原式
=2*0-1+(3/4)*(1/3)-1/2+3/4-1
=-3/2
sin^2 π/3+cos^4 3π/2-tan^2 π/3
sinπ/3=根号3/3
cos3π/2=0
tanπ/3=根号3
原式=（根号3/3）² +0^4-(根号3)²=1/3+0-3=-8/3