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1/(1+sint)对t积分重要过程或提示或思路,
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1/(1+sint)对t积分
重要过程或提示或思路,
重要过程或提示或思路,
▼优质解答
答案和解析
提示:关键是先对1/(1+sint)进行三角恒等变形.
1/(1+sint)
=(1-sint)/[(1+sint)(1-sint)]
=(1-sint)/(1-sin²t)
=(1-sint)/cos²t
=1/cos²t-sint/cos²t
∫[1/(1+sint)]dt
=∫(1/cos²t -sint/cos²t)dt
=tant + 1/cost +C
=tant +sect +C
1/(1+sint)
=(1-sint)/[(1+sint)(1-sint)]
=(1-sint)/(1-sin²t)
=(1-sint)/cos²t
=1/cos²t-sint/cos²t
∫[1/(1+sint)]dt
=∫(1/cos²t -sint/cos²t)dt
=tant + 1/cost +C
=tant +sect +C
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