[tan(2π－α)·sin(2π－α)·cos(6π－α)·sin(3π/2－α)]／[cos(－α)·sin(5π+α)·cos(3π/2－α)·sin(α－π)]

题目详情

[tan(2π－α)·sin(2π－α)·cos(6π－α)·sin(3π/2 －α)]／[cos(－α)·sin(5π+α)·cos(3π/2 －α)·sin(α－π)]

▼优质解答

答案和解析

=-tanα*(-sinα)*cosα*sinα*(-cosα)/cosα*(-sinα)*(-sinα)*(-sinα)=-1

看了 [tan(2π－α)·sin...的网友还看了以下：