一元一次方程的解法x/0.2-0.17-0.2x/0.03=10.3x+0.8/0.5-0.02x+0.03/0.03-1=0.8x-0.4/31/2{1/2[1/2(1/2x-3)]-3}-3=01/9{1/7[1/5(x+2/3+4)+6]+8}=1

Question

一元一次方程的解法
x/0.2-0.17-0.2x/0.03=1
0.3x+0.8/0.5-0.02x+0.03/0.03-1=0.8x-0.4/3
1/2{1/2[1/2(1/2x-3)]-3}-3=0
1/9{1/7[1/5(x+2/3+4)+6]+8}=1

Answer 1

0.03x/0.006-0.04x/0.006=1.17
-0.01x/0.006=1.17
-0.01x=0.00702
x=-0.702
0.3x-0.02x-0.8x=-0.4/3-1.6
-0.52x=-0.4/3-4.8/3
0.52x=5.2/3
x=10/3
1/2{1/2[1/2(1/2x-3)-3]-3}=3
1/2[1/2(1/2x-3)-3]-3=6
1/2[1/2(1/2x-3)-3]=9
1/2(1/2x-3)-3=18
1/2(1/2x-3)=21
1/2x-3=42
1/2x=45
x=90
1/7[1/5(x+2/3+4)+6]+8=9
1/7[1/5(x+2/3+4)+6]=1
1/5(x+2/3+4)+6=7
1/5(x+2/3+4)=1
x+2/3+4=5
x=5-4-2/3=1/3