积分（x^2+4x+4)/(x(x-1)^2)

题目详情

▼优质解答

答案和解析

（x^2+4x+4)/(x(x-1)^2)=4/x-3/(x-1)+9/(x-1)^2
∫（x^2+4x+4)/(x(x-1)^2)dx=∫[4/x-3/(x-1)+9/(x-1)^2]dx
=4*ln|x|-3ln|x-1|-9/(x-1)+c

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