导数运算//(u1/v)'怎么化简成u'1/v+u(1/v)'?(u/v)'=(u1/v)'=u'1/v+u(1/v)'=u'1/v+u(-1/v²)v'=u'/v-uv'/v²=(u'v-uv')/v²

题目详情

导数运算//(u*1/v)'怎么化简成u'*1/v+u*(1/v)'?
(u/v)'=(u*1/v)'
=u'*1/v+u*(1/v)'
=u'*1/v+u*(-1/v²)*v'
=u'/v-u*v'/v²
=(u'*v-u*v')/v²

▼优质解答

答案和解析

你把1/v当成一个函数f(x)=1/v(x),然后用乘法的法则展开就行了

看了导数运算//(u*1/v)'...的网友还看了以下：

导数运算//(u*1/v)'怎么化简成u'*1/v+u*(1/v)'?(u/v)'=(u*1/v)'=u'*1/v+u*(1/v)'=u'*1/v+u*(-1/v²)*v'=u'/v-u*v'/v²=(u'*v-u*v')/v²