由键盘输入一个10到99之间的整数将该数分解,分别输出其个位数和十位数字

Question

由键盘输入一个10到99之间的整数将该数分解,分别输出其个位数和十位数字

Answer 1

nt main(int argc,char* argv[])
{
char sound[10][5]={"yi","er","san","si","wu","liu","qi","ba","jiu","shi"
};
int x,y;
printf("请输入数值(1-99):");
scanf("%d",&x);
if(x<1||x>99)
printf("ERROR!超出范围.\n");
else if(x<10)
printf("%s\n",sound[x-1]);
else if(x==10)
printf("%s\n",sound[9]);
else if(x%10==0)
{y=x/10;
printf("%s-%s\n",sound[y-1],sound[9]);}
else
{ y=x/10;
x=x-y*10;
printf("%s-%s-%s\n",sound[y-1],sound[9],sound[x-1]);
}
return 0;
}