早教吧作业答案频道 -->其他-->
(1)5.63×6.34+0.563×36.6=;(2)1240×3.8+124×63-12.4×10=;(3)已知B=0.00…081992个0A=0.00…0251992个0,那么A×B=;(4)已知△÷△=□△+△=○△-△=☆□+○+☆=11.4,那么:△=
题目详情
(1)5.63×6.34+0.563×36.6=______;
(2)1240×3.8+124×63-12.4×10=______;
(3)已知B=
A=
,那么A×B=______;
(4)已知△÷△=□△+△=○△-△=☆□+○+☆=11.4,那么:△=______.
A=
,那么A×B=______;
(4)已知△÷△=□△+△=○△-△=☆□+○+☆=11.4,那么:△=______.
0.00…08 0.00…08 1992个0 1992个0
,那么A×B=______;
(4)已知△÷△=□△+△=○△-△=☆□+○+☆=11.4,那么:△=______.
0.00…025 0.00…025 1992个0 1992个0
(2)1240×3.8+124×63-12.4×10=______;
(3)已知B=
| ||
1992个0 |
| ||
1992个0 |
(4)已知△÷△=□△+△=○△-△=☆□+○+☆=11.4,那么:△=______.
| ||
1992个0 |
| ||
1992个0 |
(4)已知△÷△=□△+△=○△-△=☆□+○+☆=11.4,那么:△=______.
| ||
1992个0 |
0.00…08 |
0.00…08 |
0.00…08 |
| ||
1992个0 |
(4)已知△÷△=□△+△=○△-△=☆□+○+☆=11.4,那么:△=______.
| ||
1992个0 |
0.00…025 |
0.00…025 |
0.00…025 |
▼优质解答
答案和解析
(1)5.63×6.34+0.563×36.6,
=56.3×0.634+56.3×0.366,
=56.3×(0.634+0.366),
=56.3;
(2)1240×3.8+124×63-12.4×10,
=1240×3.8+1240×6.3-1240×0.1,
=1240×(3.8+6.3-0.1),
=1240×10,
=12400;
(3)
×
,
=
=
(4))□+〇+☆,
=△÷△+△+△+△-△,
=1+2△,
=11.4,
所以2△=10.4,因此△=5.2;
故答案为:56.3,12400,
,5.2.
0.00…025 0.00…025 0.00…0251992个0 1992个0 1992个0×
,
=
=
(4))□+〇+☆,
=△÷△+△+△+△-△,
=1+2△,
=11.4,
所以2△=10.4,因此△=5.2;
故答案为:56.3,12400,
,5.2.
0.00…08 0.00…08 0.00…081992个0 1992个0 1992个0,
=
=
(4))□+〇+☆,
=△÷△+△+△+△-△,
=1+2△,
=11.4,
所以2△=10.4,因此△=5.2;
故答案为:56.3,12400,
,5.2.
=56.3×0.634+56.3×0.366,
=56.3×(0.634+0.366),
=56.3;
(2)1240×3.8+124×63-12.4×10,
=1240×3.8+1240×6.3-1240×0.1,
=1240×(3.8+6.3-0.1),
=1240×10,
=12400;
(3)
| ||
1992个0 |
| ||
1992个0 |
=

=

(4))□+〇+☆,
=△÷△+△+△+△-△,
=1+2△,
=11.4,
所以2△=10.4,因此△=5.2;
故答案为:56.3,12400,

| ||
1992个0 |
0.00…025 |
0.00…025 |
0.00…025 |
| ||
1992个0 |
=

=

(4))□+〇+☆,
=△÷△+△+△+△-△,
=1+2△,
=11.4,
所以2△=10.4,因此△=5.2;
故答案为:56.3,12400,

| ||
1992个0 |
0.00…08 |
0.00…08 |
0.00…08 |
=

=

(4))□+〇+☆,
=△÷△+△+△+△-△,
=1+2△,
=11.4,
所以2△=10.4,因此△=5.2;
故答案为:56.3,12400,

看了 (1)5.63×6.34+0...的网友还看了以下:
还是lingo问题road(country,country):length,xie,c;endse 2020-05-13 …
计算行列式:a b 0 ...0 0 0 a b ...0 0 ............0 0 0 2020-05-16 …
ansys直接建立有限元模型问题finish/clear/prep7n,1,0,0,0n,2,0, 2020-05-17 …
线性代数与几何9.计算行列式 :1.x y ...0 00 x ...0 0" " " "0 0 2020-06-27 …
将一定质量的一块铁片,放进1.00升0.90摩/升的硫酸铜溶液中,过一段时间取出此铁片洗净烘干后称 2020-07-15 …
将一定质量的一块铁片,放进1.00升0.90摩/升的硫酸铜溶液中,过一段时间取出此铁片洗净烘干后称 2020-07-15 …
分段函数求导?设f(x)={[(1+x)^(1/x0]-e,x不等于00,x=0求f(x)在x=0 2020-07-22 …
0/0得多少0除以0等于多少,我发现一个东西0*1=0那么反起算0/0=10*2=00/0=20*3 2020-12-06 …
问两道分段函数基础题,数学底子差啊……(20)在线1,已知f(x)=大括号x^2,X>0,e,X=0 2020-12-08 …
道亨org文件中b,8,0.0000,151.6100,322.2220,184=00+184,0, 2020-12-14 …