2xm-n-5+y2m+4n-2=1是二元一次方程,求n和m?1/2xm+n-5-1/3y2m-4n+1=1

Question

2xm-n-5+y2m+4n-2=1是二元一次方程,求n和m?
1/2xm+n-5-1/3y2m-4n+1=1

Answer 1

你好2xm-n-5+y2m+4n-2=1是关于x,y的二元一次方程吧
另外还有方程为2x^(m-n-5)+y^(2m+4n-2)=1吧
即m-n-5=0,2m+4n-2=0
即m-n=5,m+2n=1
解得m=11/3,n=-4/3.