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脱式计算.3.25÷2.5÷4537×0.5÷537×0.5(0.8+1125)×12.586.27-(28.9+16.27)257-27-571.6×[1÷(2.1-2.09)].
题目详情
脱式计算.
3.25÷2.5÷4 5
×0.5÷5
×0.5 (0.8+
)×12.5 3.25÷2.5÷4 5
×0.5÷5
×0.5
×0.5÷5
×0.5
3 3 7 7
×0.5
3 3 7 7 (0.8+
)×12.5
)×12.5
1 1 125 125 86.27-(28.9+16.27) 2
-
-
1.6×[1÷(2.1-2.09)]. 86.27-(28.9+16.27) 2
-
-
-
-
5 5 7 7
-
2 2 7 7
5 5 7 7 1.6×[1÷(2.1-2.09)].
| 3.25÷2.5÷4 | 5
| (0.8+
| ||||||
| 86.27-(28.9+16.27) | 2
| 1.6×[1÷(2.1-2.09)]. |
| 3.25÷2.5÷4 | 5
| (0.8+
| ||||||
| 86.27-(28.9+16.27) | 2
| 1.6×[1÷(2.1-2.09)]. |
| 3 |
| 7 |
| 3 |
| 7 |
| 1 |
| 125 |
| 3 |
| 7 |
| 3 |
| 7 |
| 3 |
| 7 |
| 3 |
| 7 |
| 3 |
| 7 |
| 3 |
| 7 |
| 3 |
| 7 |
| 1 |
| 125 |
| 1 |
| 125 |
| 1 |
| 125 |
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
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| 7 |
▼优质解答
答案和解析
3.25÷2.5÷4
=3.25÷(2.5×4)
=3.25÷10
=0.325;
5
×0.5÷5
×0.5
=
×
÷
×
=
×
×
=
;
(0.8+
)×12.5
=0.8×12.5+
×12.5
=10+0.1
=10.1;
86.27-(28.9+16.27)
=86.27-28.9-16.27
=(86.27-16.27)-28.9
=70-28.9
=41.1;
2
-
-
=2
-(
+
)
=2
−1
=
;
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
3 3 37 7 7×0.5÷5
×0.5
=
×
÷
×
=
×
×
=
;
(0.8+
)×12.5
=0.8×12.5+
×12.5
=10+0.1
=10.1;
86.27-(28.9+16.27)
=86.27-28.9-16.27
=(86.27-16.27)-28.9
=70-28.9
=41.1;
2
-
-
=2
-(
+
)
=2
−1
=
;
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
3 3 37 7 7×0.5
=
×
÷
×
=
×
×
=
;
(0.8+
)×12.5
=0.8×12.5+
×12.5
=10+0.1
=10.1;
86.27-(28.9+16.27)
=86.27-28.9-16.27
=(86.27-16.27)-28.9
=70-28.9
=41.1;
2
-
-
=2
-(
+
)
=2
−1
=
;
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
38 38 387 7 7×
1 1 12 2 2÷
38 38 387 7 7×
1 1 12 2 2
=
×
×
=
;
(0.8+
)×12.5
=0.8×12.5+
×12.5
=10+0.1
=10.1;
86.27-(28.9+16.27)
=86.27-28.9-16.27
=(86.27-16.27)-28.9
=70-28.9
=41.1;
2
-
-
=2
-(
+
)
=2
−1
=
;
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
38 38 3814 14 14×
7 7 738 38 38×
1 1 12 2 2
=
;
(0.8+
)×12.5
=0.8×12.5+
×12.5
=10+0.1
=10.1;
86.27-(28.9+16.27)
=86.27-28.9-16.27
=(86.27-16.27)-28.9
=70-28.9
=41.1;
2
-
-
=2
-(
+
)
=2
−1
=
;
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
1 1 14 4 4;
(0.8+
)×12.5
=0.8×12.5+
×12.5
=10+0.1
=10.1;
86.27-(28.9+16.27)
=86.27-28.9-16.27
=(86.27-16.27)-28.9
=70-28.9
=41.1;
2
-
-
=2
-(
+
)
=2
−1
=
;
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
1 1 1125 125 125)×12.5
=0.8×12.5+
×12.5
=10+0.1
=10.1;
86.27-(28.9+16.27)
=86.27-28.9-16.27
=(86.27-16.27)-28.9
=70-28.9
=41.1;
2
-
-
=2
-(
+
)
=2
−1
=
;
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
1 1 1125 125 125×12.5
=10+0.1
=10.1;
86.27-(28.9+16.27)
=86.27-28.9-16.27
=(86.27-16.27)-28.9
=70-28.9
=41.1;
2
-
-
=2
-(
+
)
=2
−1
=
;
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
5 5 57 7 7-
-
=2
-(
+
)
=2
−1
=
;
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
2 2 27 7 7-
=2
-(
+
)
=2
−1
=
;
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
5 5 57 7 7
=2
-(
+
)
=2
−1
=
;
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
5 5 57 7 7-(
+
)
=2
−1
=
;
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
2 2 27 7 7+
5 5 57 7 7)
=2
−1
=
;
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160. 2
5 5 57 7 7−1
=
;
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
5 5 57 7 7;
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
=3.25÷(2.5×4)
=3.25÷10
=0.325;
5
| 3 |
| 7 |
| 3 |
| 7 |
=
| 38 |
| 7 |
| 1 |
| 2 |
| 38 |
| 7 |
| 1 |
| 2 |
=
| 38 |
| 14 |
| 7 |
| 38 |
| 1 |
| 2 |
=
| 1 |
| 4 |
(0.8+
| 1 |
| 125 |
=0.8×12.5+
| 1 |
| 125 |
=10+0.1
=10.1;
86.27-(28.9+16.27)
=86.27-28.9-16.27
=(86.27-16.27)-28.9
=70-28.9
=41.1;
2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
| 3 |
| 7 |
| 3 |
| 7 |
=
| 38 |
| 7 |
| 1 |
| 2 |
| 38 |
| 7 |
| 1 |
| 2 |
=
| 38 |
| 14 |
| 7 |
| 38 |
| 1 |
| 2 |
=
| 1 |
| 4 |
(0.8+
| 1 |
| 125 |
=0.8×12.5+
| 1 |
| 125 |
=10+0.1
=10.1;
86.27-(28.9+16.27)
=86.27-28.9-16.27
=(86.27-16.27)-28.9
=70-28.9
=41.1;
2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
| 3 |
| 7 |
=
| 38 |
| 7 |
| 1 |
| 2 |
| 38 |
| 7 |
| 1 |
| 2 |
=
| 38 |
| 14 |
| 7 |
| 38 |
| 1 |
| 2 |
=
| 1 |
| 4 |
(0.8+
| 1 |
| 125 |
=0.8×12.5+
| 1 |
| 125 |
=10+0.1
=10.1;
86.27-(28.9+16.27)
=86.27-28.9-16.27
=(86.27-16.27)-28.9
=70-28.9
=41.1;
2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
| 38 |
| 7 |
| 1 |
| 2 |
| 38 |
| 7 |
| 1 |
| 2 |
=
| 38 |
| 14 |
| 7 |
| 38 |
| 1 |
| 2 |
=
| 1 |
| 4 |
(0.8+
| 1 |
| 125 |
=0.8×12.5+
| 1 |
| 125 |
=10+0.1
=10.1;
86.27-(28.9+16.27)
=86.27-28.9-16.27
=(86.27-16.27)-28.9
=70-28.9
=41.1;
2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
| 38 |
| 14 |
| 7 |
| 38 |
| 1 |
| 2 |
=
| 1 |
| 4 |
(0.8+
| 1 |
| 125 |
=0.8×12.5+
| 1 |
| 125 |
=10+0.1
=10.1;
86.27-(28.9+16.27)
=86.27-28.9-16.27
=(86.27-16.27)-28.9
=70-28.9
=41.1;
2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
| 1 |
| 4 |
(0.8+
| 1 |
| 125 |
=0.8×12.5+
| 1 |
| 125 |
=10+0.1
=10.1;
86.27-(28.9+16.27)
=86.27-28.9-16.27
=(86.27-16.27)-28.9
=70-28.9
=41.1;
2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
| 1 |
| 125 |
=0.8×12.5+
| 1 |
| 125 |
=10+0.1
=10.1;
86.27-(28.9+16.27)
=86.27-28.9-16.27
=(86.27-16.27)-28.9
=70-28.9
=41.1;
2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
| 1 |
| 125 |
=10+0.1
=10.1;
86.27-(28.9+16.27)
=86.27-28.9-16.27
=(86.27-16.27)-28.9
=70-28.9
=41.1;
2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160. 2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
| 5 |
| 7 |
1.6×[1÷(2.1-2.09)].
1.6×(1÷0.01)
=1.6×100
=160.
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