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脱式计算，能简算的要简算．149+587+5175×0.5+15×0.58×35×12.5201-315÷15（3.8-1.8÷2）×0.534÷[（45+14）×37]
题目详情
脱式计算，能简算的要简算．
149+587+51 75×0.5+15×0.5 8×
×12.5 201-315÷15 （3.8-1.8÷2）×0.5
÷[（
+
）×
]149+587+51 75×0.5+15×0.5 8×
×12.5 149+587+51 75×0.5+15×0.5 8×
×12.5
×12.5
3 5 3 3 5 5 201-315÷15 （3.8-1.8÷2）×0.5
÷[（
+
）×
]201-315÷15 （3.8-1.8÷2）×0.5
÷[（
+
）×
]
÷[（
+
）×
]
3 4 3 3 4 4
+
）×
]
4 5 4 4 5 5
）×
]
1 4 1 1 4 4
]
3 7 3 3 7 7
| 149+587+51 | 75×0.5+15×0.5 | 8×
| ||||||||
| 201-315÷15 | （3.8-1.8÷2）×0.5 |
|
| 149+587+51 | 75×0.5+15×0.5 | 8×
| ||||||||
| 201-315÷15 | （3.8-1.8÷2）×0.5 |
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▼优质解答
答案和解析
（1）149+587+51
=149+51+587
=200+587
=787；
（2）75×0.5+15×0.5
=（75+15）×0.5
=90×0.5
=45；
（3）8×
×12.5
=8×12.5×
=100×
=60；
（4）201-315÷15
=201-21
=180；
（5）（3.8-1.8÷2）×0.5
=（3.8-0.9）×0.5
=2.9×0.5
=1.45；
（6）
÷[（
+
）×
]
=
÷[
×
]
=
÷
=
．
3 5 3 3 35 5 5×12.5
=8×12.5×
=100×
=60；
（4）201-315÷15
=201-21
=180；
（5）（3.8-1.8÷2）×0.5
=（3.8-0.9）×0.5
=2.9×0.5
=1.45；
（6）
÷[（
+
）×
]
=
÷[
×
]
=
÷
=
．
3 5 3 3 35 5 5
=100×
=60；
（4）201-315÷15
=201-21
=180；
（5）（3.8-1.8÷2）×0.5
=（3.8-0.9）×0.5
=2.9×0.5
=1.45；
（6）
÷[（
+
）×
]
=
÷[
×
]
=
÷
=
．
3 5 3 3 35 5 5
=60；
（4）201-315÷15
=201-21
=180；
（5）（3.8-1.8÷2）×0.5
=（3.8-0.9）×0.5
=2.9×0.5
=1.45；
（6）
÷[（
+
）×
]
=
÷[
×
]
=
÷
=
．
3 4 3 3 34 4 4÷[（
+
）×
]
=
÷[
×
]
=
÷
=
．
4 5 4 4 45 5 5+
）×
]
=
÷[
×
]
=
÷
=
．
1 4 1 1 14 4 4）×
]
=
÷[
×
]
=
÷
=
．
3 7 3 3 37 7 7]
=
÷[
×
]
=
÷
=
．
3 4 3 3 34 4 4÷[
×
]
=
÷
=
．
21 20 21 21 2120 20 20×
]
=
÷
=
．
3 7 3 3 37 7 7]
=
÷
=
．
3 4 3 3 34 4 4÷
=
．
9 20 9 9 920 20 20
=
．
5 3 5 5 53 3 3．
=149+51+587
=200+587
=787；
（2）75×0.5+15×0.5
=（75+15）×0.5
=90×0.5
=45；
（3）8×
| 3 |
| 5 |
=8×12.5×
| 3 |
| 5 |
=100×
| 3 |
| 5 |
=60；
（4）201-315÷15
=201-21
=180；
（5）（3.8-1.8÷2）×0.5
=（3.8-0.9）×0.5
=2.9×0.5
=1.45；
（6）
| 3 |
| 4 |
| 4 |
| 5 |
| 1 |
| 4 |
| 3 |
| 7 |
=
| 3 |
| 4 |
| 21 |
| 20 |
| 3 |
| 7 |
=
| 3 |
| 4 |
| 9 |
| 20 |
=
| 5 |
| 3 |
| 3 |
| 5 |
=8×12.5×
| 3 |
| 5 |
=100×
| 3 |
| 5 |
=60；
（4）201-315÷15
=201-21
=180；
（5）（3.8-1.8÷2）×0.5
=（3.8-0.9）×0.5
=2.9×0.5
=1.45；
（6）
| 3 |
| 4 |
| 4 |
| 5 |
| 1 |
| 4 |
| 3 |
| 7 |
=
| 3 |
| 4 |
| 21 |
| 20 |
| 3 |
| 7 |
=
| 3 |
| 4 |
| 9 |
| 20 |
=
| 5 |
| 3 |
| 3 |
| 5 |
=100×
| 3 |
| 5 |
=60；
（4）201-315÷15
=201-21
=180；
（5）（3.8-1.8÷2）×0.5
=（3.8-0.9）×0.5
=2.9×0.5
=1.45；
（6）
| 3 |
| 4 |
| 4 |
| 5 |
| 1 |
| 4 |
| 3 |
| 7 |
=
| 3 |
| 4 |
| 21 |
| 20 |
| 3 |
| 7 |
=
| 3 |
| 4 |
| 9 |
| 20 |
=
| 5 |
| 3 |
| 3 |
| 5 |
=60；
（4）201-315÷15
=201-21
=180；
（5）（3.8-1.8÷2）×0.5
=（3.8-0.9）×0.5
=2.9×0.5
=1.45；
（6）
| 3 |
| 4 |
| 4 |
| 5 |
| 1 |
| 4 |
| 3 |
| 7 |
=
| 3 |
| 4 |
| 21 |
| 20 |
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=
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| 9 |
| 20 |
=
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=
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=
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