2/t^2-1的原函数是ln（t-1）/t+1为啥?

Question

2/t^2-1的原函数是ln（t-1）/t+1 为啥?

Answer 1

2/t^2-1=1/(t-1)-1/(t+1)
所以,其原函数是ln(t-1)-ln(t+1)+C=ln[(t-1)/(t+1)]+C