x^2-2x+y^2+6y+10=0,求分式(x-y)/(x+y)

题目详情

x^2 - 2x + y^2 + 6y + 10 = 0,求分式 (x-y)/(x+y)

▼优质解答

答案和解析

X＾2+Y＾2-2X-6Y+10=0
(X-1)^2+(Y-3)^2=0
X-1=0;Y-3=0
X=1,Y=3
(x-y)/(x+y)
=-1/2

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