早教吧作业答案频道 -->数学-->
sin4π/3cos5π/6tan(－4π/3)怎么做,求详细过程sin4π/3乘以cos5π/6乘以tan(－4π/3)=？
题目详情
sin4π/3cos5π/6tan(－4π/3)怎么做,求详细过程
sin4π/3乘以cos5π/6乘以tan(－4π/3)=？
sin4π/3乘以cos5π/6乘以tan(－4π/3)=？
▼优质解答
答案和解析
sin cos的周期为2π tan周期为π
sin4π=sin(4π-4π)=sin0=0
3cos5π=3cos(5π-4π)=3cosπ=3*(-1)=-3
6tan(－4π/3)=6tan(－4π/3+π)=6tan(-π/3)=-6tan(π/3)=-6√3
sin4π=sin(4π-4π)=sin0=0
3cos5π=3cos(5π-4π)=3cosπ=3*(-1)=-3
6tan(－4π/3)=6tan(－4π/3+π)=6tan(-π/3)=-6tan(π/3)=-6√3
看了 sin4π/3cos5π/6...的网友还看了以下：