用递等式计算．①28.49÷7.4×0.32；②（514÷1.25+112）×13-0.975；③（0.2+13）÷23÷0.6；④[（615-0.45）÷1518]÷（113÷6）．

Question

用递等式计算．
①28.49÷7.4×0.32；            
②（5(1)/(4)÷1.25+1(1)/(2)）×(1)/(3)-0.975；
③（0.2+(1)/(3)）÷(2)/(3)÷0.6；         
④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）．

(1)/(4)÷1.25+1(1)/(2)）×(1)/(3)-0.975；
③（0.2+(1)/(3)）÷(2)/(3)÷0.6；         
④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）．(1)/(4)1144(1)/(2)）×(1)/(3)-0.975；
③（0.2+(1)/(3)）÷(2)/(3)÷0.6；         
④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）．(1)/(2)1122(1)/(3)-0.975；
③（0.2+(1)/(3)）÷(2)/(3)÷0.6；         
④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）．(1)/(3)1133
(1)/(3)）÷(2)/(3)÷0.6；         
④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）．(1)/(3)1133(2)/(3)÷0.6；         
④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）．(2)/(3)2233
(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）．(1)/(5)1155(5)/(18)]÷（1(1)/(3)÷6）．(5)/(18)551818(1)/(3)÷6）．(1)/(3)1133

Answer 1

①28.49÷7.4×0.32
=3.85×0.32
=1.232；

②（5(1)/(4)÷1.25+1(1)/(2)）×(1)/(3)-0.975
=（4.2+1.5）×(1)/(3)-0.975
=5.7×(1)/(3)-0.975
=1.9-0.975
=0.925；

③（0.2+(1)/(3)）÷(2)/(3)÷0.6
=(8)/(15)×(3)/(2)×(5)/(3)
=(4)/(3)；

④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）
=[(23)/(4)÷1(5)/(18)]÷(2)/(9)
=(9)/(2)×(9)/(2)
=(81)/(4)． (1)/(4)111444÷1.25+1(1)/(2)）×(1)/(3)-0.975
=（4.2+1.5）×(1)/(3)-0.975
=5.7×(1)/(3)-0.975
=1.9-0.975
=0.925；

③（0.2+(1)/(3)）÷(2)/(3)÷0.6
=(8)/(15)×(3)/(2)×(5)/(3)
=(4)/(3)；

④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）
=[(23)/(4)÷1(5)/(18)]÷(2)/(9)
=(9)/(2)×(9)/(2)
=(81)/(4)． (1)/(2)111222）×(1)/(3)-0.975
=（4.2+1.5）×(1)/(3)-0.975
=5.7×(1)/(3)-0.975
=1.9-0.975
=0.925；

③（0.2+(1)/(3)）÷(2)/(3)÷0.6
=(8)/(15)×(3)/(2)×(5)/(3)
=(4)/(3)；

④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）
=[(23)/(4)÷1(5)/(18)]÷(2)/(9)
=(9)/(2)×(9)/(2)
=(81)/(4)． (1)/(3)111333-0.975
=（4.2+1.5）×(1)/(3)-0.975
=5.7×(1)/(3)-0.975
=1.9-0.975
=0.925；

③（0.2+(1)/(3)）÷(2)/(3)÷0.6
=(8)/(15)×(3)/(2)×(5)/(3)
=(4)/(3)；

④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）
=[(23)/(4)÷1(5)/(18)]÷(2)/(9)
=(9)/(2)×(9)/(2)
=(81)/(4)． (1)/(3)111333-0.975
=5.7×(1)/(3)-0.975
=1.9-0.975
=0.925；

③（0.2+(1)/(3)）÷(2)/(3)÷0.6
=(8)/(15)×(3)/(2)×(5)/(3)
=(4)/(3)；

④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）
=[(23)/(4)÷1(5)/(18)]÷(2)/(9)
=(9)/(2)×(9)/(2)
=(81)/(4)． (1)/(3)111333-0.975
=1.9-0.975
=0.925；

③（0.2+(1)/(3)）÷(2)/(3)÷0.6
=(8)/(15)×(3)/(2)×(5)/(3)
=(4)/(3)；

④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）
=[(23)/(4)÷1(5)/(18)]÷(2)/(9)
=(9)/(2)×(9)/(2)
=(81)/(4)． (1)/(3)111333）÷(2)/(3)÷0.6
=(8)/(15)×(3)/(2)×(5)/(3)
=(4)/(3)；

④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）
=[(23)/(4)÷1(5)/(18)]÷(2)/(9)
=(9)/(2)×(9)/(2)
=(81)/(4)． (2)/(3)222333÷0.6
=(8)/(15)×(3)/(2)×(5)/(3)
=(4)/(3)；

④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）
=[(23)/(4)÷1(5)/(18)]÷(2)/(9)
=(9)/(2)×(9)/(2)
=(81)/(4)． (8)/(15)888151515×(3)/(2)×(5)/(3)
=(4)/(3)；

④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）
=[(23)/(4)÷1(5)/(18)]÷(2)/(9)
=(9)/(2)×(9)/(2)
=(81)/(4)． (3)/(2)333222×(5)/(3)
=(4)/(3)；

④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）
=[(23)/(4)÷1(5)/(18)]÷(2)/(9)
=(9)/(2)×(9)/(2)
=(81)/(4)． (5)/(3)555333
=(4)/(3)；

④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）
=[(23)/(4)÷1(5)/(18)]÷(2)/(9)
=(9)/(2)×(9)/(2)
=(81)/(4)． (4)/(3)444333；

④[（6(1)/(5)-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）
=[(23)/(4)÷1(5)/(18)]÷(2)/(9)
=(9)/(2)×(9)/(2)
=(81)/(4)． (1)/(5)111555-0.45）÷1(5)/(18)]÷（1(1)/(3)÷6）
=[(23)/(4)÷1(5)/(18)]÷(2)/(9)
=(9)/(2)×(9)/(2)
=(81)/(4)． (5)/(18)555181818]÷（1(1)/(3)÷6）
=[(23)/(4)÷1(5)/(18)]÷(2)/(9)
=(9)/(2)×(9)/(2)
=(81)/(4)． (1)/(3)111333÷6）
=[(23)/(4)÷1(5)/(18)]÷(2)/(9)
=(9)/(2)×(9)/(2)
=(81)/(4)． (23)/(4)232323444÷1(5)/(18)]÷(2)/(9)
=(9)/(2)×(9)/(2)
=(81)/(4)． (5)/(18)555181818]÷(2)/(9)
=(9)/(2)×(9)/(2)
=(81)/(4)． (2)/(9)222999
=(9)/(2)×(9)/(2)
=(81)/(4)． (9)/(2)999222×(9)/(2)
=(81)/(4)． (9)/(2)999222
=(81)/(4)． (81)/(4)818181444．