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直接写出得数.26+26=26-26=1-56=25+35=810-510=34+14=16+46=410+510=89-69=78-26=27+27=1-37=90×6=300×4=500×7=72÷8=2000×5=44+8=1300-500=4800÷4=11×9=32÷8=5600+400=800+200=240×4=15×6=100-43=37-18=
题目详情
直接写出得数.
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| 90×6= | 300×4= | ||||||||||||||||||||||||||
| 500×7= | 72÷8= | 2000×5= | 44+8= | 1300-500= | 4800÷4= | 11×9= | ||||||||||||||||||||||||||
| 32÷8= | 5600+400= | 800+200= | 240×4= | 15×6= | 100-43= | 37-18= |
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▼优质解答
答案和解析
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=0
1-
=
+
=1
-
=
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=1
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=
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=
+
=
2 2 26 6 6+
=
2 2 26 6 6=
2 2 23 3 3
-
=0
-
=0
2 2 26 6 6-
=0
2 2 26 6 6=0
1-
=
1-
=
5 5 56 6 6=
1 1 16 6 6
+
=1
+
=1
2 2 25 5 5+
=1
3 3 35 5 5=1
-
=
-
=
8 8 810 10 10-
=
5 5 510 10 10=
3 3 310 10 10
+
=1
+
=1
3 3 34 4 4+
=1
1 1 14 4 4=1
+
=
+
=
1 1 16 6 6+
=
4 4 46 6 6=
5 5 56 6 6
+
=
-
=
-
=
+
=
1-
=
+
=
+
=
4 4 410 10 10+
=
5 5 510 10 10=
9 9 910 10 10
-
=
-
=
8 8 89 9 9-
=
6 6 69 9 9=
2 2 29 9 9
-
=
-
=
7 7 78 8 8-
=
2 2 26 6 6=
13 13 1324 24 24
+
=
+
=
2 2 27 7 7+
=
2 2 27 7 7=
4 4 47 7 71-
=
1-
=
3 3 37 7 7=
举报
问题解析 问题解析
(1)同分母分数相加减,分母不变,只把分子相加减;
(2)异分母分数相加减,先通分成同分母,再分母不变,只把分子相加减;
(3)整数的四则运算,按照运算方法口算得解. (1)同分母分数相加减,分母不变,只把分子相加减;
(2)异分母分数相加减,先通分成同分母,再分母不变,只把分子相加减;
(3)整数的四则运算,按照运算方法口算得解.名师点评 名师点评
本题考点: 本题考点:
分数的加法和减法;整数的加法和减法;整数的乘法及应用;整数的除法及应用. 分数的加法和减法;整数的加法和减法;整数的乘法及应用;整数的除法及应用.
考点点评: 考点点评:
此题考查简单的分数和整数的四则运算,属于基本试题,注意认真分析式中数据,然后快速准确得出答案;注意如果是分数的结果,要化简成最简分数. 此题考查简单的分数和整数的四则运算,属于基本试题,注意认真分析式中数据,然后快速准确得出答案;注意如果是分数的结果,要化简成最简分数.
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作业帮用户
2017-10-01
举报
作业帮用户作业帮用户
2017-10-012017-10-01
举报
- 问题解析
- (1)同分母分数相加减,分母不变,只把分子相加减;
(2)异分母分数相加减,先通分成同分母,再分母不变,只把分子相加减;
(3)整数的四则运算,按照运算方法口算得解.
(2)异分母分数相加减,先通分成同分母,再分母不变,只把分子相加减;
(3)整数的四则运算,按照运算方法口算得解.
(2)异分母分数相加减,先通分成同分母,再分母不变,只把分子相加减;
(3)整数的四则运算,按照运算方法口算得解.
- 名师点评
-
- 本题考点:
- 分数的加法和减法;整数的加法和减法;整数的乘法及应用;整数的除法及应用.
-
- 考点点评:
- 此题考查简单的分数和整数的四则运算,属于基本试题,注意认真分析式中数据,然后快速准确得出答案;注意如果是分数的结果,要化简成最简分数.
- 本题考点:
- 分数的加法和减法;整数的加法和减法;整数的乘法及应用;整数的除法及应用.
- 本题考点:
- 分数的加法和减法;整数的加法和减法;整数的乘法及应用;整数的除法及应用.
- 考点点评:
- 此题考查简单的分数和整数的四则运算,属于基本试题,注意认真分析式中数据,然后快速准确得出答案;注意如果是分数的结果,要化简成最简分数.
- 考点点评:
- 此题考查简单的分数和整数的四则运算,属于基本试题,注意认真分析式中数据,然后快速准确得出答案;注意如果是分数的结果,要化简成最简分数.
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var userCity = "\u4e50\u5c71",
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