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用递等式计算.(1)0.48+10.8÷0.36×0.54(2)[9.08-(0.61+1.75)]+3.2(3)1314-1528÷58+14(4)45÷[(34-23)÷58].
题目详情
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用递等式计算. (1)0.48+10.8÷0.36×0.54 | (2)[9.08-(0.61+1.75)]+3.2 | ||||||||||||||||
(3)
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用递等式计算. (1)0.48+10.8÷0.36×0.54 | (2)[9.08-(0.61+1.75)]+3.2 | ||||||||||||||||
(3)
| (4)
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用递等式计算. (1)0.48+10.8÷0.36×0.54 | (2)[9.08-(0.61+1.75)]+3.2 | ||||||||||||||||
(3)
| (4)
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用递等式计算. (1)0.48+10.8÷0.36×0.54 | (2)[9.08-(0.61+1.75)]+3.2 | ||||||||||||||||
(3)
| (4)
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用递等式计算. (1)0.48+10.8÷0.36×0.54 | (2)[9.08-(0.61+1.75)]+3.2 | ||||||||||||||||
(3)
| (4)
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(1)0.48+10.8÷0.36×0.54
(2)[9.08-(0.61+1.75)]+3.2
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(1)0.48+10.8÷0.36×0.54
(2)[9.08-(0.61+1.75)]+3.2
(1)0.48+10.8÷0.36×0.54
(2)[9.08-(0.61+1.75)]+3.2
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▼优质解答
答案和解析
(1)0.48+10.8÷0.36×0.54,=0.48+30×0.54,=0.48+16.2,=16.68;(2)[9.08-(0.61+1.75)]+3.2,=[9.08-2.36]+3.2,=6.72+3.2,=9.92;(3) 13 14 - 15 28 ÷ 5 8 + ...
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