计算方程组s=2(t-9)+3(t-5),s=(t+3)/2-(t+2)/3拜托了,答得好我一定加分,过程要详细.

Question

计算方程组s=2(t-9)+3(t-5),s=(t+3)/2-(t+2)/3
拜托了,答得好我一定加分,过程要详细.

Answer 1

s=2(t-9)+3(t-5) (1)
s=(t+3)/2-(t+2)/3 (2)
化简（1）得：
s=5t-33 带入（2）得：
5t-33=(t+3)/2-(t+2)/3
解t=7
则s=2