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1/2(t-4)(4t-16)+1/2[(4t-16)+(t-1)]×3-1/2(t-1)(t-1)=(麻烦用笔写下来,要完整的过程,谢谢!)
题目详情
1/2(t-4)(4t-16)+1/2[(4t-16)+(t-1)]×3-1/2(t-1)(t-1
)=(麻烦用笔写下来,要完整的过程,谢谢!)
)=(麻烦用笔写下来,要完整的过程,谢谢!)
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答案和解析
1/2(t-4)(4t-16)+1/2[(4t-16)+(t-1)]×3-1/2(t-1)(t-1)=
1/2(t-4)(4t-16)+3/2(4t-16)+3/2(t-1)-1/2(t-1)(t-1)=
1/2(4t-16)[(t-4)+3]+1/2(t-1)[3-(t-1)]=
1/2(4t-16)(t-1)+1/2(t-1)(4-t)=
4/2(t-4)(t-1)-1/2(t-1)(t-4)=
3/2(t-4)(t-1)
1/2(t-4)(4t-16)+3/2(4t-16)+3/2(t-1)-1/2(t-1)(t-1)=
1/2(4t-16)[(t-4)+3]+1/2(t-1)[3-(t-1)]=
1/2(4t-16)(t-1)+1/2(t-1)(4-t)=
4/2(t-4)(t-1)-1/2(t-1)(t-4)=
3/2(t-4)(t-1)
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