因式分解作业速答(a+b)²-(a-b)²(m+1)²-9(m-1)²(m+2n)²-(m-n)²a²-b²+ac+bc(x+y)²-z²a²-(b-c)²(m-a)²-(n+b)²9(m+n)²-(m-n)²第
(a+b)²-(a-b)²
(m+1)²-9(m-1)²
(m+2n)²-(m-n)²
a²-b²+ac+bc
(x+y)²-z²
a²-(b-c)²
(m-a)²-(n+b)²
9(m+n)²-(m-n)²
第一二三和最后两道就不用了,已经会了
=[(a+b)+(a-b)][(a+b)-(a-b)]
=2a*2b
=4ab
(m+1)²-9(m-1)²
=[(m+1)+3(m-1)][(m+1)-3(m-1)]
=(4m-2)(-2m+4)
=-4(2m-1)(m-2)
(m+2n)²-(m-n)²
=[(m+2n)+(m-n)][(m+2n)-(m-n)]
=(2m+n)*3n
=3n(2m+n)
a²-b²+ac+bc
=(a+b)(a-b)+c(a+b)
=(a+b)(a-b+c)
(x+y)²-z²
=[(x+y)+z][(x+y)-z]
=(x+y+z)(x+y-z)
a²-(b-c)²
=[a+(b-c)][a-(b-c)]
=(a+b-c)(a-b+c)
(m-a)²-(n+b)²
=[(m-a)+(n+b)][(m-a)-(n+b)]
=(m+n-a+b)(m-n-a-b)
9(m+n)²-(m-n)²
=[3(m+n)+(m-n)][3(m+n)-(m-n)]
=(4m+2n)(2m+4n)
=4(2m+n)(m+2n)
在等腰梯形ABCD中,AD‖BC,E为AB的中点,过点E作EF‖BC交CD于点F.AB=4,BC= 2020-05-16 …
如图,在△ABC中,∠C=90°,AC=6,BC=8,M是BC的中点,动点P在AB边上运动(点P不 2020-05-24 …
如图,在Rt△ABC中,AB=3,BC=4,∠ABC=90°,过B作BA1⊥AC,过A1作A1B1 2020-06-07 …
如图,在Rt△ABC中,AB=3,BC=4,∠ABC=90°,过B作BA1⊥AC,过A1作A1B1 2020-06-13 …
已知:如图,在Rt△ABC中,∠C=90°,∠ABC=60°,BC长为3p,BBl是∠ABC的平分 2020-07-09 …
如图,在△ABC中,∠C=90°,AC=6,BC=8,M是BC的中点,动点P在AB边上运动(点P不 2020-07-30 …
如图,在Rt△ABC中,AB=3,BC=4,∠ABC=90°,过B作BA1⊥AC,过A1作A1B1⊥ 2020-10-30 …
如图,在Rt△ABC中,AB=3,BC=4,∠ABC=90°,过B作BA1⊥AC,过A1作A1B1⊥ 2020-10-31 …
如图,已知直角三角形ACB,AC=3,BC=4,过直角顶点C作CA1⊥AB,垂足为A1,再过A1作A 2020-10-31 …
如图,等腰Rt△ABC的直角边长为32,从直角顶点A作斜边BC的垂线交BC于D1,再从D1作D1D2 2020-10-31 …