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已知函数f（x）=sin(2x+4/π)+sin(2χ-4/π）1.化简并求出函数f（χ）的最小周期T内容详细点
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已知函数f（x）=sin(2x+4/π)+sin(2χ-4/π）1.化简并求出函数f（χ）的最小周期T 【内容详细点】
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答案和解析
f(x)=sin(2x+π/4)+sin(2x-π/4)
=sin2xcosπ/4+cos2xsinπ/4+sin2xcosπ/4-cos2xsinπ/4
=2sin2xcosπ/4
=2*√2/2sin2x
=√2sin2x
T=2π/2=π
=sin2xcosπ/4+cos2xsinπ/4+sin2xcosπ/4-cos2xsinπ/4
=2sin2xcosπ/4
=2*√2/2sin2x
=√2sin2x
T=2π/2=π
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