化简 [a^2-1]/[a-1]-√[a^2-2a+1]/a^2-a]化简后带入a=1/[2+√3]

Question

化简 [a^2-1]/[a-1]-√[a^2-2a+1]/a^2-a]
化简后带入a=1/[2+√3]

Answer 1

a=1/[2+√3]=(2-√3)/(2+√3)(2-√3)=2-√3
1/a=2+√3
a-1<0
于是
原式
=(a+1)(a-1)/(a-1)-√(a-1)²/[a(a-1)]
=(a+1)+(a-1)/[a(a-1)]
=a+1+1/a
=2-√3+1+(2+√3)
=3-√3+2+√3
=5